The reaction of sodium acetate with acetyl ch | vedclass

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(A) The reaction between sodium acetate $(CH_3COO^-Na^+)$ and acetyl chloride $(CH_3COCl)$ is a nucleophilic acyl substitution reaction.In this mechan

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(A) The reaction between sodium acetate $(CH_3COO^-Na^+)$ and acetyl chloride $(CH_3COCl)$ is a nucleophilic acyl substitution reaction.In this mechanism,the acetate ion $(CH_3COO^-)$ acts as a nucleophile.The nucleophilic oxygen atom of the acetate ion attacks the electrophilic carbonyl carbon of the acetyl chloride molecule.This attack results in the formation of a tetrahedral intermediate,where the carbonyl carbon is bonded to the acetate oxygen,the methyl group,the chlorine atom,and the original carbonyl oxygen (which now carries a negative charge).Therefore,the correct mechanism involves the acetate ion attacking the carbonyl carbon of acetyl chloride to form a tetrahedral intermediate.

List-$I$	List-$II$
$(a)$ $R-COCl \to R-CHO$	$(i)$ $Br_2 / NaOH$
$(b)$ $R-CH_2-COOH \to R-CH(Cl)-COOH$	$(ii)$ $H_2 / Pd-BaSO_4$
$(c)$ $R-CONH_2 \to R-NH_2$	$(iii)$ $Zn(Hg) / \text{Conc. } HCl$
$(d)$ $R-CO-CH_3 \to R-CH_2-CH_3$	$(iv)$ $Cl_2 / \text{Red } P, H_2O$

List-$I$ (Test)	List-$II$ (Identification)
$A$. Bayer's test	$I$. Phenol
$B$. Ceric ammonium nitrate test	$II$. Aldehyde
$C$. Phthalein dye test	$III$. Alcoholic-$OH$ group
$D$. Schiff's test	$IV$. Unsaturation

The reaction of sodium acetate with acetyl chloride proceeds through which of the following mechanisms?

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